0=-4.9t^2+7t+0.6

Solution for 0=-4.9t^2+7t+0.6 equation:

0=-4.9t^2+7t+0.6

We move all terms to the left:

0-(-4.9t^2+7t+0.6)=0

We add all the numbers together, and all the variables

-(-4.9t^2+7t+0.6)=0

We get rid of parentheses

4.9t^2-7t-0.6=0

a = 4.9; b = -7; c = -0.6;
Δ = b2-4ac
Δ = -72-4·4.9·(-0.6)
Δ = 60.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{60.76}}{2*4.9}=\frac{7-\sqrt{60.76}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{60.76}}{2*4.9}=\frac{7+\sqrt{60.76}}{9.8}
$